Solution 2_ Java Program to Count and Map Character Reversals in a String- Interview Question Asked in TCS, Wipro, Deloitte, Tech-Mahindra
### Explanation of the Java Program
This Java program counts the frequency of each character in a given string and stores the results in a `HashMap`. The key of the `HashMap` represents the character, and the value represents the number of times that character appears in the string.
#### Detailed Breakdown of the Code:
1. **Initialization**: - The input string `str` is initialized with the value `"deepakkumar"`.
- The string is converted to a character array `ch` using the method `toCharArray()`. This array will be used to iterate over each character in the string.
2. **Creating the HashMap**:
- A `HashMap map` is instantiated to store each character (as the key) and its frequency (as the value).
3. **Iterating Over Characters**:
- A `for` loop is used to iterate over each character `c` in the character array `ch`.
- For each character `c`, the program checks if it is already present in the `HashMap` using `map.containsKey(c)`.
4. **Updating the HashMap**:
- **If the character is already in the `HashMap`**:
- The program increments the frequency count of that character by 1 using `map.put(c, map.get(c) + 1)`.
- **If the character is not in the `HashMap`**:
- The program adds the character to the `HashMap` with an initial frequency of 1 using `map.put(c, 1)`.
5. **Printing the Result**:
- After processing all characters, the `HashMap map` is printed to the console, showing each character and its corresponding frequency.
### Example Execution:
For the input string `"deepakkumar"`, the program processes each character and updates the `HashMap` as follows:
- **Processing 'd'**:
- Not in the `HashMap`, so it's added with a count of `1` → `{d=1}`.
- **Processing 'e'**:
- Not in the `HashMap`, so it's added with a count of `1` → `{d=1, e=1}`.
- **Processing the second 'e'**:
- Already in the `HashMap`, so its count is incremented by `1` → `{d=1, e=2}`.
- **Continue processing** for each character similarly.
### Example Output:
Given the input `"deepakkumar"`, the output of the program will be:
### Key Points:
- **Character Frequency Count**: The program effectively counts the number of occurrences of each character in the string.
- **HashMap Usage**: The use of a `HashMap` allows for efficient storage and retrieval of character counts, making the solution scalable for larger strings.
- **Simplicity and Efficiency**: The program provides a straightforward and efficient way to analyze character distribution within a string.
This Java program counts the frequency of each character in a given string and stores the results in a `HashMap`. The key of the `HashMap` represents the character, and the value represents the number of times that character appears in the string.
#### Detailed Breakdown of the Code:
1. **Initialization**: - The input string `str` is initialized with the value `"deepakkumar"`.
- The string is converted to a character array `ch` using the method `toCharArray()`. This array will be used to iterate over each character in the string.
2. **Creating the HashMap**:
- A `HashMap
3. **Iterating Over Characters**:
- A `for` loop is used to iterate over each character `c` in the character array `ch`.
- For each character `c`, the program checks if it is already present in the `HashMap` using `map.containsKey(c)`.
4. **Updating the HashMap**:
- **If the character is already in the `HashMap`**:
- The program increments the frequency count of that character by 1 using `map.put(c, map.get(c) + 1)`.
- **If the character is not in the `HashMap`**:
- The program adds the character to the `HashMap` with an initial frequency of 1 using `map.put(c, 1)`.
5. **Printing the Result**:
- After processing all characters, the `HashMap map` is printed to the console, showing each character and its corresponding frequency.
### Example Execution:
For the input string `"deepakkumar"`, the program processes each character and updates the `HashMap` as follows:
- **Processing 'd'**:
- Not in the `HashMap`, so it's added with a count of `1` → `{d=1}`.
- **Processing 'e'**:
- Not in the `HashMap`, so it's added with a count of `1` → `{d=1, e=1}`.
- **Processing the second 'e'**:
- Already in the `HashMap`, so its count is incremented by `1` → `{d=1, e=2}`.
- **Continue processing** for each character similarly.
### Example Output:
Given the input `"deepakkumar"`, the output of the program will be:
### Key Points:
- **Character Frequency Count**: The program effectively counts the number of occurrences of each character in the string.
- **HashMap Usage**: The use of a `HashMap` allows for efficient storage and retrieval of character counts, making the solution scalable for larger strings.
- **Simplicity and Efficiency**: The program provides a straightforward and efficient way to analyze character distribution within a string.
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